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Points: (k, 3h) and (3k, h)

Slope: h-3h/3k-k = -2h/2k => -h/k

Equation: y-3h = -h/k(x-k) => ky-3hk = -h(x-k) => ky = -hx+hk+3hk

Equation in its general form: hx+ky-4hk = 0

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Q: What is the straight line equation in its general form connected by the end points of k 3h and 3k h on the Cartesian plane showing work?
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