49 + 2 + 7 = 58
49 x 2 x 7 = 686
49/2 + 14/2 = 63/2 or 31 and 1/2
49/2 x 7 = 343/2 or 171 and 1/2
7(7 + 9)
Two integers that have a sum of -7 and a product of 12 are -3 and -4.
product = 2 x 7 = 14 [sum = 2 + 7 = 9]
13
Call your number "x", write an equation, and solve it: 8x = x + 49 7x = 49 x = 7
7(7 + 9)
the sum of 10 and the product of 7 and a number 2+5=7 2*5=10
Two integers that have a sum of -7 and a product of 12 are -3 and -4.
product = 2 x 7 = 14 [sum = 2 + 7 = 9]
13
7
Call your number "x", write an equation, and solve it: 8x = x + 49 7x = 49 x = 7
X + 7 = 49 =======
7 and 11
49.
Find the product of 7 and the sum of 8 and 10
Let the numbers by 'm' & 'n' Hence m + n = 12 mn = 35 Hence m = 35/n Substitute 35/n + n = 12 Multiply through by 'n' 35 + n^2 = 12n n^2 - 12n + 35 = 0 It is now in Quadratic Form ; Factor ( n - 7)(n - 5) = 0 Hence n= 7 or n= 5 It follows that m = 5 , or m = 7