500
200 + 300 + 250 = 750
The sum of the integers between 101 and 300 inclusive is equal to ((101+300) x 200) / 2 = 40100.
Sum means adding together two numbers, so the answere would be 300.
K is a set of five consecutive prime numbers such that the sum of all the elements in K is greater than 200 and less than 300. Which of the following cannot be the sum of the elements in the set K?
300.
300 Find the difference (500-100=400) then halve the sum(200). Add the halved sum to the lowest number in the equaion(100) or subtract the halved sum(200)from the largest number in the equation(500) one:500-100=400 two:400/2=200 Three: 200+100=300 or 500-200=300
500
200 + 100 = 300
Since the first integer of the 3-digit numbers must be 2, the sum of the second and the third digits would be 13.Since the largest digit is 9, the 3-digit numbers could be 249, 294, 258, 285, 267, and 276.Thus, there are 6 integers between 200 and 300 whose sum of their digits is 15.
300 multiplied by 200 is 60,000
(200+300)/2 = 250
Percentage of 200 to 300 is 50%.