207
The three are 204/3 - 1, 204/3 and 204/3 + 1 ie 67, 68 and 69
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
The sum of three consecutive integers starting with ( n ) can be expressed as ( n + (n + 1) + (n + 2) ). Simplifying this expression gives ( 3n + 3 ). Therefore, the sum of the three consecutive integers is ( 3n + 3 ) or ( 3(n + 1) ).
24 + 25 + 26 = 75
The numbers are 23, 24 and 25.
The three are 204/3 - 1, 204/3 and 204/3 + 1 ie 67, 68 and 69
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.
201
They are are 62, 63 and 64.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
The sum of even integers cannot end with 9. why not
The sum of three consecutive integers starting with ( n ) can be expressed as ( n + (n + 1) + (n + 2) ). Simplifying this expression gives ( 3n + 3 ). Therefore, the sum of the three consecutive integers is ( 3n + 3 ) or ( 3(n + 1) ).
-3,-4,-5
The integers are 24, 25 and 26.
24 + 25 + 26 = 75
The integers are 16, 17 and 18.