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The three are 204/3 - 1, 204/3 and 204/3 + 1 ie 67, 68 and 69

It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.

201

They are are 62, 63 and 64.

3 consecutive even integers whose sum is 396 are 130, 132 and 134.

Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.

The sum of even integers cannot end with 9. why not

The integers are 24, 25 and 26.

The integers are 4, 5 and 6.

The integers are 16, 17 and 18.

24 + 25 + 26 = 75

73,74,75

The numbers are 23, 24 and 25.

Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.

It isn't possible to solve that. The sum of three consecutive integers is always a multiple of 3 (try it out with a few small numbers); 125 is not a multiple of 3, ergo, the problem has no solution.

-3,-4,-5

The integers are are 41, 42 and 43.

The integers are -1, 1 and 3.

The integers are 26, 27 and 28. Using just oddconsecutive integers you have 25, 27 and 29.

Divide the sum of the three consecutive odd integers by 3: -273 /3 = -91. The smallest of these integers will be two less than -91 and the largest will be two more than -91, so the three consecutive odd integers will be -89, -91, and -93.

31, 32, 33

4 and 5

88,89,90 the answer is 88, 89,90.

50, 51, 52

38, 39, 40