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What are two consecutive even integers whose sum is 72?
There are none. However, the two odd numbers are 35 and 37.
Find two consecutive odd integers whose sum is 72?
Two consecutive odd integers are 'X' and 'X+2' . X + (X + 2) = 72 2X + 2 = 72 2X = 70 X = 35 X + 2 = 37
What is the sum of three consecutive odd integers that is -72?
Let's denote the three consecutive odd integers as x, x+2, and x+4. Since they are odd integers, they are separated by 2 units. The sum of these integers can be represented as x + (x+2) + (x+4) = 3x + 6. Given that the sum is -72, we can set up the equation 3x + 6 = -72 and solve for x. Subtracting 6 from both sides, we get 3x = -78. Dividing by 3, we find x = -26. Therefore, the sum of the three consecutive odd integers is -72.
Four consecutive odd integers whose sum is -72?
The numbers are -21, -19, -17 and -15.
Find two consecutive integers whose sum is 72?
There are no two consecutive integers that add up to 72. You can prove it this way: Let our numbers be represented by the variables "a" and "b". We are told: a = b + 1 a + b = 72 So we can use substitution to solve for either variable: (b + 1) + b = 72 2b + 1 = 72 2b = 71 b = 35.5 But 35.5 is not an integer, so this condition can not be met.
