There are none. However, the two odd numbers are 35 and 37.
Two consecutive odd integers are 'X' and 'X+2' . X + (X + 2) = 72 2X + 2 = 72 2X = 70 X = 35 X + 2 = 37
Let's denote the three consecutive odd integers as x, x+2, and x+4. Since they are odd integers, they are separated by 2 units. The sum of these integers can be represented as x + (x+2) + (x+4) = 3x + 6. Given that the sum is -72, we can set up the equation 3x + 6 = -72 and solve for x. Subtracting 6 from both sides, we get 3x = -78. Dividing by 3, we find x = -26. Therefore, the sum of the three consecutive odd integers is -72.
The numbers are -21, -19, -17 and -15.
There are no two consecutive integers that add up to 72. You can prove it this way: Let our numbers be represented by the variables "a" and "b". We are told: a = b + 1 a + b = 72 So we can use substitution to solve for either variable: (b + 1) + b = 72 2b + 1 = 72 2b = 71 b = 35.5 But 35.5 is not an integer, so this condition can not be met.
The sum of three consecutive integers is -72
The even integers are 22, 24 and 26.
There are none. However, the two odd numbers are 35 and 37.
Two consecutive odd integers are 'X' and 'X+2' . X + (X + 2) = 72 2X + 2 = 72 2X = 70 X = 35 X + 2 = 37
Presumably the sum is -222, as defined by the question!
72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.
Let's denote the three consecutive odd integers as x, x+2, and x+4. Since they are odd integers, they are separated by 2 units. The sum of these integers can be represented as x + (x+2) + (x+4) = 3x + 6. Given that the sum is -72, we can set up the equation 3x + 6 = -72 and solve for x. Subtracting 6 from both sides, we get 3x = -78. Dividing by 3, we find x = -26. Therefore, the sum of the three consecutive odd integers is -72.
The numbers are -21, -19, -17 and -15.
There are no two consecutive integers that add up to 72. You can prove it this way: Let our numbers be represented by the variables "a" and "b". We are told: a = b + 1 a + b = 72 So we can use substitution to solve for either variable: (b + 1) + b = 72 2b + 1 = 72 2b = 71 b = 35.5 But 35.5 is not an integer, so this condition can not be met.
Since the three integers are consecutive, let them be: m, m+1, and m+2.Then:m + (m+1) + (m+2) = 72m + m + 1 + m + 2 = 3m + 3 = 723(m+1) = 72m+1 = 24m = 23So the three integers are: {23, 24, 25}. Check and they do in fact sum to 72.
The numbers are 8 and 9.
35 and 37.