0
$1.91
6 = 150
3 = 30
2 = 10
1 = 1
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What is the sum of three quarters plus thress quarters?
six quarters. That is equal to one and half.
Is it possible to change 15 dollars into an equal number of half-dollars quarters and dimes?
A set of half dollar quarter and dime is worth 50+25+10 = 85 cents. So, with an equal number of these coins the sum can only be a multiple of 85 cents. 15 dollars is not a multiple so cannot be so changed.
What are 5 coins that have a total value of 1.05. Four of the coins are the same and their sum is a multiple of 10. What coins does Darla have?
She has 4 quarters and a nickel.
When you estimate the sum of 2 fractions the estimate is never a whole number?
The sum of two fractions will only be a whole number if the fractions have a common denominator. When the denominators are different, the sum will be a fraction with a different denominator, making it impossible to be a whole number. Thus, estimating the sum of two fractions will generally result in a fraction, not a whole number.
What is the sum of a pentacontakaipentagon?
A shape does not have a sum. The angles of a shape have a sum, the lengths of its sides have a sum, the number of its diagonals are a sum, but the shape itself certainly does not have any sum!
Robert found 24 coins 13 of them were pennies 14 of them were nickels 16 of them were dimes and the rest were quarters how many pennies dimes nickels and quarters did Robert find?
The question suggests that there are 24 coins. 13 of them are pennies, 14 are nickels, and 16 are dimes and the rest are quarters. To answer this question, One would add the number of pennies, nickels, and dimes and subtract the sum of those coins from 24. The difference of the two numbers would be the amount of quarters. However, 13+14+16=43. 24-43= -19 There can't be -19 quarters.
How many ways can you make 2.50 from quarters and dimes?
2.50 can be made up from 10 quarters or 25 dimes, for the first two ways. The smallest number of quarters that can be substituted for dimes without changing the sum is two, substituted for five dimes. Therefore, you can have: 20 dimes + 2 quarters, 15 dimes + 4 quarters, 10 dimes + 6 quarters, or 5 dimes + 8 quarters, four additional possibilities for a total of six..
A change machine gives change in quarters and dimes if you receive 12 coins after inserting a dollar bill how many quarters did you receive?
A dime = $0.10 A quarter = $0.25 You have received 12 coins as a mixture of dimes and quarters. The minimum value of those 12 coins is 12 of the smaller denomination coin, ie the 12 dimes: The sum of 12 dimes is 12 × $0.10 = $1.20 If you replace a dime by a quarter it will create a larger sum as: you remove $0.10 but add $0.25 giving a difference of -$0.10 + $0.25 = $0.15 → the change machine is clearly not working correctly. as the sum of the 12 coins must be at least $1.20 and you only inserted a dollar. ----------- However, if the machine gives change in quarters and nickels, then: a nickel = $0.05 a quarter = $0.25 12 nickels = 12 × $0.25 = $0.60 Every time a nickel is replaced by a quarter the effect is to subtract $0.05 and add $0.25 to make an overall difference of -$0.05 + $0.25 = $0.20 → increase the sum by $0.20 $1.00 - $0.60 = $0.40 $0.40 ÷ $0.20 = 2 → replace 2 nickels by quarters and the total value is $1.00 → 10 nickels + 2 quarters = 10 × $0.05 + 2 × $0.25 = $0.50 + $0.50 = $1.00 The machine gave you 10 nickels and 2 quarters.
The coins in a cash register total 12.50 and there are only nickels dimes and quarters. There are twice as many dimes as nickels and there are twice as many quarters as dimes. How many of each coin?
There are 10 nickels, 20 dimes and 40 quarters in the cash register. The 10 nickels is 10 x 5 cents or 50 cents. The 20 dimes is 20 x 10 cents or 200 cents. The 40 quarters is 40 x 25 cents or 1000 cents. Converting and adding these, we get $0.50 + $2.00 + $10.00 = $12.50, which is the sum given in the question. Let's work through it. The number of nickels is N, the number of dimes is D and the number of quarters is Q. These are our variables in this problem. We don't know how many of them there are, and their numbers could vary. That's why we call them variables. We might also call them unknowns, too. A nickel is 5 cents, so the value of the nickels is the number of nickels, which is N, times the value of the nickel, which is 5 cents. That's 5N here. A dime is 10 cents, so the value of the dimes is the number of dimes, which is D, times the value of the dime, which is 10 cents. That's 10D here. A quarter is 25 cents, so the value of the quarters is the number of quarters, which is Q, times the value of the quarter, which is 25 cents. That's 25Q here. The sum of the values of the coins was given as $12.50, or 1250 cents, because we are working with coins, whose values are measured in cents. Further, we can write this expression as 5N + 10D + 25Q = 1250 on our way to the answer. Of the last two facts, the first was that there were twice as many dimes as nickels. We could write that as D = 2N because said another way, there are twice the number of dimes as nickels. We might also say that for every nickel, there are 2 dimes, so doubling the number of nickels will give us the number of dimes. The last fact is that there were twice as many quarters as dimes. We could write that as Q = 2D because said another way, thre are twice the number of quarters as dimes. We might also say that for every dime, there are 2 quarters, so doubling the number of dimes will give us the number of quarters. The last two bits of data we have allow us to solve the problem, because the do something special for us. Each bit of data expresses one variable in terms of another. That means we can make substitutions in our expressions for the sum of the values of the coins. Let's put up or original expression, and then do some substitutions. 5N + 10D + 25Q = 1250 This is the original expression. We know that D = 2N, so lets put the 2N in where we see D and expand things a bit. 5N + 10(2N) + 25Q = 1250 5N + 20N + 25Q = 1250 We changed the "look" of the expression, but we didn't change its value. Let's go on. We know that Q = 2D, so lets put that in. 5N + 20N + 25Q = 1250 5N + 20N + 25(2D) = 1250 5N + 20N + 50D = 1250 We're almost there. Remember that D = 2N, and we can substitute that in here. 5N + 20N + 50D = 1250 5N + 20N + 50(2N) = 1250 5N + 20N + 100N = 1250 Groovy! We have substituted variables and now have an expression with only one variable in it! Let's proceed. 5N + 20N + 100N = 1250 125N = 1250 We're close! N = 1250/125 = 10 N = 10 The number of nickels is 10, and because the nickel is 5 cents, the value of these coins is their number times their value, or 10 x 5 cents = 50 cents = $0.50 We were told the number of dimes was twice the number of nickels. This means that since there are 10 nickels, there will 2 x 10 or 20 dimes. And 20 x 10 cents = 200 cents = $2.00 We were also told the number of quarters was twice the number of dimes. This means that since there are 20 dimes, there will be 2 x 20 or 40 quarters. And 40 x 25 cents = 1,000 cents = $10.00 If we add the values of the coins, we should get the $12.50 that we were told was in the register. $0.50 + $2.00 + $10.00 = $12.50 We're in business. The value of each denomination of coins adds up to the given value of all the coins in the register. Piece of cake.
You have 35 coins that total a dollar you have the same number of dimes and nickels what coins do you have?
Since the smallest of these currency values (the nickel) is equal to 5 cents, the number of five cent coins that go into a dollar is equal to 20. It is impossible to have a combination of 35 nickels and dimes whose sum is exactly equal to a dollar.
What is the sum of three quarters plus thress quarters?
six quarters. That is equal to one and half.
How do you make 0.21 using only nickels pennies and dimes using 5 or more coins?
one dime = $0.10 plus one nickel = $0.15 plus 6 pennies = $0.21 *Used a total of 8 coins to make a sum of $0.21.*
What is better getting 100000 at once or getting a penny whose sum is doubled everyday for 31 days?
Take the penny a day doubled every day. The sum would be almost 43,000,000.
How many nickels in 2.80 dollars?
There are 56 nickels in $2.80. 56 * 0.05 = 2.80 That's really an easy sum to do - I hope your teacher will explain to you how to do it.
Shelby has a total of 10 quarters and dimes in his pocket These coins total 1.60 How many dimes are in his pocket?
25Q + 10D = 160 Q + D = 10 ==> 10Q + 10D = 100 Subtract: 15Q = 60 ==> Q = 4, and then D = 6 Check: 4 times 25 cents = $1.00, 6 times 10 cents = 60 cents, sum = $1.60
Shelby has a total of 10 quarters and dimes in his pocket. These coins total $1.60. How many dimes are in his pocket?
25Q + 10D = 160 Q + D = 10 ==> 10Q + 10D = 100 Subtract: 15Q = 60 ==> Q = 4, and then D = 6 Check: 4 times 25 cents = $1.00, 6 times 10 cents = 60 cents, sum = $1.60
What is the sum of one penny a day doubled for thirty one days?
$21,474,836.48
