700 + 300 = 1,000
700
1000-300 = 700
1700
300.
700*3/7 = 300
The range is 400. (700 - 300 = 400)
700
The sum of the integers from 1 through 300 is 44,850.
8400
prime numbers from 300 to 700:307,311,313,317,331,337,347,349,353,359,367, 373,379,383,389,397,401,409,419,421,431,433, 439,443,449,457,461,463,467,479,487,491,499, 503,509,521,523,541,547,557,563,569,571,577, 587,593,599,601,607,613,617,619,631,641,643, 647,653,659,661,673,677,683,691
700 + 700 + 700 = 2100As the question is stated, the first two numbers are dimensionless, and only the third number has dimensions of dollars. Very technically then, the sum is: 1,400 + $700. However, we can reasonably surmise that the questioner intended for each of the three numbers to have the same dimensions. If this is true, then the sum is: $700 + $700 + $700 = $2,100
(300 x (300 + 1)) / 2 = 45150 Therefore, the sum of all the integers from 1 to 300 is 45150.