Q: What is the sum of 8 1over4 and 1 7over11?

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66/8 - 53/8 = 13/8 or 1 and 5/8

5 over 8 :)

The sum of 1 + 8 is 9.

The sum of 1 and 7 is 8. That is, 1 + 7 = 8

The sum of 1/8 and 3/8 is 1/2

1 + 8 = 9

The sum is: 8

8 + 1 equals 9

8 and 1 8+1=9 8*1=8

There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }

+8 and +1

The two numbers are 1 and 8 1*8=8 1+8=9

9

9

8 and 1 8*1=8 8+1=9

3/8 + 1/8 = 1/2

17

15

The sum of 1/2 and 5/8 is 1 1/8

8 times 1 = 8 8+1=9

8

It is: 1*4+1*8 = 12

It is: 8+1+7 = 16

0.125

9