23
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
9+9+8+8+7+6=47. I do it this way: (9+9)+(8+8)+(7+6).
27 is the sum : 4 + 6+ 8 + 9 = 27
It could be: (4*8)+(9-6) = 35
The sum of 6 feet 10 inches and 8 feet 9 inches is: 15 feet 7 inches.
52
To find six numbers with a mean (average) of 9, we can choose numbers such that their sum equals 6 multiplied by 9, which is 54. Here's one possible set of numbers: 10 10 9 9 8 8 The sum of these numbers is 54, and when you divide the sum by 6 (the number of values), you get the mean of 9.
The sum of 8 and 6 is 14 (8+6)
The sum of 1 + 8 is 9.
The sum of -8 and 6 is -2
The sum of 6 ft 10 inches and 8 ft 9 inches is 15.5833333 feet or 15 feet 7 inches.
6 + 7 + 8 + 9 + 10 + 11 = 51