Digits are from 1 to 9
the sum of the 9 greatest digits is = 9+9+9+9+9+9+9+9+9 = 81
the sum of the 9 lowest digits is = 1+1+1+1+1+1+1+1+1+1= 9
and so :
81 + 9 = 90
The sum of the digits on a digital clock is the greatest when the time is 9:59. At this time, the sum of the digits is 9 + 5 + 9 = 23. This is the highest possible sum because the maximum value for each digit on a digital clock is 9.
-9
It is: 999 => 9+9+9 = 27 => 2+7 => 9
Yes, a number is a factor of 9 if the sum of its digits equals 9 or is a multiple of 9. This is based on the divisibility rule for 9, which states that a number is divisible by 9 if the sum of its digits is divisible by 9. Therefore, if the sum of the digits is 9, the number itself is divisible by 9.
The sum of the digits is also a multiple of 9. And, if the sum of the digits is too large, you can sum those digits and keep going.
A number is divisible by 9 if the sum of its digits is divisible by 9. Thus, the number 99999 is divisible by 9 (the sum of its digits is 45, and it is clearly 11111 * 9), and because 99999 is the largest 5 digit number, it must be the largest 5 digit multiple of 9. 99999 is the greatest no divisible by 9.if u divide it u`ll get 11111.
The sum of the digits is a multiple of 9
No factor of 9 has three digits. 450 is a three-digit multiple of 150 (and of 9) with a digit sum of 9.
The sum of the digits in 252 is 2 + 5 + 2 which equals 9.
10 9+9+1 = 19 1+9=10
The rule to decide if a number is divisible by 9 is to look at the sum of the digits. If the sum of the digits is divisible by 9, then so is the number.
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)