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What is the sum of a 6-term geometric series if the first term is 21 and the last term is 352947?
Wiki User
ā 10y ago
U1 = a = 21
U6 = ar5 = 352947
where Un is the nth term, with first term, a, and commn ratio r.
Dividing the second equation by the first, r5 = 16807
Taking the fifth root, r = 7.
The S6 = a*(r6 - 1)/(r - 1) = 21*(76-1)/(7-1) = 411768
Wiki User
ā 10y ago
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