4x - 8 = 8(x + 2)
4*(2x + 8) = 32
Not necessarily. If the number is 0, then the sum of 8 times the number and -192 is -192.
There is nothing in the description you have given which tells us the amount of that unspecified number, therefore, the answer could be anything. If you want to solve for an unknown number you need an equation. You might have said four times a number added to -9 subtracted from triple the sum of nine times the number and eight is equal to zero. Then we can solve the equation.
The sum of four and negative eight is negative four.
N = the number It's [ 7N + (N+8) ]
6x + 4 = 5x x = -4
8(5 + x), or 8x + 40.
Let's call the number XTwice the number would be 2XFour times the same number would be 4XThe sum of these two is 2X + 4X = 6XThe answer is therefore six times the number.
Let the number be x and so if 8x +1 = 7x then x = -1
Suppose the number is x. The sum of the number and two is x+2 Four times the sum is 4(x+2) The number times 8 is 8x 24 less than the number times 8 is 8x-24 4(x+2) = 8x-24 4x+8=8x-24 so 4x = 32 and x = 8
Let's represent the # with x 4x-8=8(x+2) 4x-8=8x+16 4x-8x=16+8 -4x=24 x=24/-4 x=-6 The number is -6
six times the sum of eight and eight 6*(8+8) = 96add eight to eight and multiply the result by six.
The larger number is 12.
Four times the unknown number. Let's say the unknown number is x. x + 3x = 4x
The sum of four and the product of three and a number xxxx.
Assuming the number is n; then: 2n + (6n + 5) = 8n + 5 That means five added to eight times the number