Given that n + 6 = 200,
subtract 6 from each side,
n = 200 - 6 = 194
An odd number.
x+6
3% of 200 = 6
I am an even three digit number If you round me to the nearest ten I become 200 The sum of my digets is 18 What number am I?
199 If it's 200 rounded to nearest ten, then the number must be between 195 and 205. Only 199 has the correct digit sum.
6 + N where N is the unspecified number.
(6+n) n= a number
n + 46n + 46
The number has six digits. Examples: 123,542 329,634 999,999 438,873
199
12
Sum of an arithmetic series:Sum = (1st number + last number) x (the number of numbers) /2Your first number is 2. Your last number is 2 x 100 = 200. The number of numbers in this series is 100 (says so in the question). So your sum equals:(2 + 200) x 100 / 2 = 202 x 100 / 2 = 10100.