The sum of angles in degree = 180(n - 2), where n is the number of sides of the regular polygon. The sum of angles in degree = 180(n - 2); n = 8 The sum of angles in degree = 180(8 - 2) = 180(6) = 1,080 Angle in degree = (The sum of angles in degree)/n Angle in degree = (1,080)/8 = 135 Thus, in a regular octagon, the degree of an angle is 135.
The sum of angles of a regular polygon in degrees = 180(n - 2), where n is the number of sides of the regular polygon. So, where n = 8 the sum of angles in degree = 180(8 - 2) = 180(6) = 1,080 Angle in degree = (The sum of angles in degree)/n Angle in degree = (1,080)/8 = 135 Thus, in a regular octagon, the degree of an angle is 135.
360 degree.
360 degree
S of interior angles of ANY n-sided polygon is (2n -4) right angles, so 2 x 30 - 4 = 56, 56 x 90 = 5040 degrees
The sum of the exterior angles of any regular polygon is 360°
180 degree( 5-2) is the sum of the interior angles. Now divide this by 5 since it is regular and that tells us all the angles have the same measure.
What is the sum of the measures of the exterior angles of a regular polygon with ten sides
Sum of angles in a regular polygon = (#sides - 2) * 180. Sum of Octagon angles = (8-2) * 180 = 1080
180 DEGREE
A Regular Polygon
The sum of the exterior angles of any polygon is 360 degrees.