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For any n-sided regular polygon, the sum of the internal angles of the polygon is equal to (n - 2) x 180. In this instance, the sum of the internal angles of a 14-sided shape is equal to (14 - 2) x 180 = 2160 degrees.

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Q: What is the sum of the degrees of the internal angles of a tetradecagon?
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What is the degresase of a tetradecagon?

The sum of the internal angles of any regular polygon can be determined by 180 x (n - 2), where n is the number of sides. In this instance, since a tetradecagon has 14 sides, the sum of the internal angles is equal to 180 x (14 - 2) = 180 x 12 = 2160 degrees. Dividing this by the number of sides gives us the number of degrees in each one of the angles. In this instance, 2160 / 14 = 154 and two sevenths, or 154.285714 recurring degrees.


What is the sum of the internal angles of a triacontakaihexagon?

The sum of the internal angles of any regular polygon is (n - 2) x 180 degrees. Since a triacontakaihexagon has 36 sides, the sum of the internal angles of a triacontakaihexagon has a sum of internal angles of (36 - 2) x 180 = 6120 degrees.


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The sum of the internal angles of any triangle is 180 degrees. Any rectangle has four 90 degree internal angles, totalling 360 degrees.


How many angles does a petagon have?

the sum of the internal angles is 540 degrees


What is the sum of the internal angles of a square?

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The internal angles add to 180 degrees.


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Each angle is 120 degrees. Six vertices multiplied by 120 degrees each gives you 720 degrees as the sum of the internal angles.


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The sum of the internal angles is 180*(11 - 2) = 180*9 = 1620 degrees. The sum of the external angles is 360 degrees - irrespective of the number of sides.


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The sum of the internal angles of a pentagon is 540 degrees.