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The sum of the first 1400 odd numbers is 1960000.
The sum of an arithmetic progression is given by:
sum = n/2 (2a + (n-1)d)
where n is the number of items (in this case n = 1400)
where a is the first number (in this case a = 1)
where d is the common difference between terms (in this case d = 2)
Thus:
sum = 1400/2 × (2×1 + (1400 - 1)×2)
→ sum = 1400/2 × 2(1 + 1400 - 1)
→ sum = 1400 × 1400 = 1960000
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