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Q: What is the sum of the first 30 positive integers?

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30*62 = 1860

The sum of the first 30 positive even numbers is 930.

The sum of the first 30 positive even numbers is 930.

The product is 30.

810. All of the integers from -30 to30 cancel each other out by adding a negative to a positive. Then all you need to do is add the integers from 31 to 50. (31 + 32 + ....+50)

There is no conjecture about the sum of the first 30 positive even numbers. The answer can be derived and proven. A statement that has been proven is no longer a conjecture.

I'll assume you mean the first 30 positive integers, and not real numbers. That would be 31 X 15, or 465. 30 + 1 = 31, 29 + 2 = 31, 28 + 3 = 31, etc. This can happen 15 times, with 15 + 16 = 31 being the fifteenth.

The integers are even and are 28 and 30.

The integers are -30, -28 and -26.

The integers are -16 and -14.

They are 28, 29 and 30.

They're all positive integers under 30.

The integers are 27, 28, 29 and 30.

The integers are 6, 7, 8 and 9.

6,7,8,9

9+10+11=30

It is 0.

27 + 28 + 29 + 30 = 114

The numbers are -31, -30 and -29.

11

33

The answer to what is the sum of the first positive even numbers is 930. It doesn't mean that you add all the even numbers up until you reach the number 30. In fact, since you have to get the sum of the even numbers, you have to add all even numbers until you get to the number 60.

25, 26, 27, 28, 29, 30

The arithmetic sequence of odd integers is 1, 3, 5, 7, 9, ... where the common difference is 2. The sum of the first thirty odd integers can be found by using the sum formula such as: Sn = n/2[2a1 + (n - 1)d], where a1 = 1, n = 30, and d = 2. So, S30 = (30/2)[(2)(1) + (30 - 1)(2)] = (15)[2 + (29)(2)] = (15)(60) = 900

-30 and -28

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