The sum of the first 30 positive even numbers is 930.
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The sum of the first 30 positive integers is: 465.
Let's take a look at this. For any integer n, 2n always be even, then the next consecutive number 2n + 1 must be odd. Let add them first, 2n + 2n + 1 = 4n + 1 = 2(2n) + 1 So their sum is odd, since every even number multiplied by 2 is also even. Let's multiplied them, 2n(2n + 1) = (2n)^2 + 2n Their product is even, since every even number raised in the second power is also even, and the sum of two even numbers is even too. So the answer is that when the sum of two numbers can be odd, their product is an even number. (note that the sum of two odd numbers is even)
n2+n
If the negative has a greater absolute value, the sum will be negative. If the positive has a greater absolute value, the sum will be positive.
No, it is always false. Perimeter of a rectangle= 2l + 2w, l= length, w=width. 2*any whole number, regardless odd or even, is even. Thus 2l is even and 2w is even. The sum of two even numbers is always even.