The formula to sum a series of numbers is:
sum = 1/2 x number_of_numbers x (first_number + last_number)
So to sum the integers 5 to 500:
From 5 to 500 there are 500 - 5 + 1 = 496 integers, so
sum = 1/2 x 496 x (5 + 500)
= 125240
No. The sum of all integers between 1 and 500 is 124,749.
5 & 10
The integers are -7 and -5.
-2,2,9
No, the sum of two negative integers is not a positive integer. For example, if you add -5 and -6 together the sum would be -11.
The sum of the first 500 positive integers is: 125,250
No. The sum of all integers between 1 and 500 is 124,749.
The sum of the first 500 positive integers is: 1 + 2 + 3 + ... + 498 + 499 + 500 = 125250
The answer is -5.
490.
-4 and -5
Zero (0).
5 & 10
-4 and -1
The integers are -7 and -5.
It need not be. 2 and 3 are consecutive integers and their sum is 5, not 31.
There's a trick to this one. Let 1 + 2 + ... + 500 be the sum of all integers 1 to 500, called X Now, imagine we want to add the sum the integers from 1 to 500 and to the sum of the integers from 1 to 500. This would give us 2*X we can write it as 1 + 2 + ... + 500 + 1 + 2 + ... + 500 But that's not particularly useful. What if we look at it as: 1 + 2 + ... + 499 + 500 + 500 + 499 + ... + 2 + 1 adding the numbers that are directly on top of each other, we get 500 + 1 = 501, 499 + 2 = 501... 1 + 500 = 501 Thus every term is 501, and we have 500 terms. So, we have 501*500 = 2X Thus X, the sum from 1 to 500, is (500*501)/2 = 125,250