There's a trick to this one. Let 1 + 2 + ... + 500 be the sum of all integers 1 to 500, called X
Now, imagine we want to add the sum the integers from 1 to 500 and to the sum of the integers from 1 to 500. This would give us 2*X
we can write it as
1 + 2 + ... + 500
+
1 + 2 + ... + 500
But that's not particularly useful. What if we look at it as:
1 + 2 + ... + 499 + 500
+
500 + 499 + ... + 2 + 1
adding the numbers that are directly on top of each other, we get
500 + 1 = 501, 499 + 2 = 501... 1 + 500 = 501
Thus every term is 501, and we have 500 terms. So, we have 501*500 = 2X
Thus X, the sum from 1 to 500, is (500*501)/2 = 125,250
The formula n*(n+1) is used to find the sum of n positive integers. Th sum of positive integers up to 500 can be calculated as 250*251=62,750.
-499
The sum of the first 500 positive integers is: 1 + 2 + 3 + ... + 498 + 499 + 500 = 125250
All integers from 1 to 200.
This may or may not be true. The set of "counting numbers" may either be defined as all positive integers (1, 2, 3, 4...) or as all non-negative integers (0, 1, 2, 3, 4...). Similarly, the set of "whole numbers" may be defined as all positive integers, all non-negative integers, or as all integers (...-3, -2, -1, 0, 1, 2, 3...). It all depends on the definition given for each term.
No. The sum of all integers between 1 and 500 is 124,749.
95
The formula n*(n+1) is used to find the sum of n positive integers. Th sum of positive integers up to 500 can be calculated as 250*251=62,750.
When adding negative integers, you subtract. (2+-1=1) When subtracting negative integers, you add. (2--3=5)
The formula to sum a series of numbers is: sum = 1/2 x number_of_numbers x (first_number + last_number) So to sum the integers 5 to 500: From 5 to 500 there are 500 - 5 + 1 = 496 integers, so sum = 1/2 x 496 x (5 + 500) = 125240
-499
To find the number of integers from 1 to 500 that are divisible by 7, we need to determine the number of multiples of 7 within this range. The first multiple of 7 in this range is 7, and the last multiple is 497. To find the count, we divide the last multiple by 7 and subtract the first multiple divided by 7, then add 1 (to include the first multiple). So, 497/7 - 7/7 + 1 = 71 - 1 + 1 = 71. Therefore, there are 71 integers from 1 to 500 that are divisible by 7.
It's easy to work it out yourself.... Multiply 100 by 49, add 50, add 100 - and you have your answer !
+2 + -1= 1
Usually all the integers (counting numbers) from 1 to 100.Usually all the integers (counting numbers) from 1 to 100.Usually all the integers (counting numbers) from 1 to 100.Usually all the integers (counting numbers) from 1 to 100.
The sum of the first 500 positive integers is: 1 + 2 + 3 + ... + 498 + 499 + 500 = 125250
The sum of all integers from 1 to 20 inclusive is 210.