0
There's a trick to this one. Let 1 + 2 + ... + 500 be the sum of all integers 1 to 500, called X
Now, imagine we want to add the sum the integers from 1 to 500 and to the sum of the integers from 1 to 500. This would give us 2*X
we can write it as
1 + 2 + ... + 500
+
1 + 2 + ... + 500
But that's not particularly useful. What if we look at it as:
1 + 2 + ... + 499 + 500
+
500 + 499 + ... + 2 + 1
adding the numbers that are directly on top of each other, we get
500 + 1 = 501, 499 + 2 = 501... 1 + 500 = 501
Thus every term is 501, and we have 500 terms. So, we have 501*500 = 2X
Thus X, the sum from 1 to 500, is (500*501)/2 = 125,250
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
What is the sum of all even integers from 2 to 500 inclusive?
The formula n*(n+1) is used to find the sum of n positive integers. Th sum of positive integers up to 500 can be calculated as 250*251=62,750.
If you add all the numbers from 1-500 together what is it?
-499
What is the sum of the first 500 numbers?
The sum of the first 500 positive integers is: 1 + 2 + 3 + ... + 498 + 499 + 500 = 125250
What are the multiples of the 1 from 1 to 200?
All integers from 1 to 200.
How do you add numbers 1 through 500?
The best trick for this is to think of averages. Put the 1 with 500, 2 with 499,, 3 with 488, ... On average these numbers are (1 + 500)/2 or 250.5 So you want to add up 500 numbers each of which is, on average 250.5 The answer is 500 x 250.5 which is 125250
Is 95 the sum of integers between 1 and 500?
No. The sum of all integers between 1 and 500 is 124,749.
How many times does the digit 9 appear in the list of all integers from 1 to 500?
95
What is the sum of all even integers from 2 to 500 inclusive?
The formula n*(n+1) is used to find the sum of n positive integers. Th sum of positive integers up to 500 can be calculated as 250*251=62,750.
How do you add and subbtract positive and negative integers?
When adding negative integers, you subtract. (2+-1=1) When subtracting negative integers, you add. (2--3=5)
What is the sum of the integers from 5 to 500?
The formula to sum a series of numbers is: sum = 1/2 x number_of_numbers x (first_number + last_number) So to sum the integers 5 to 500: From 5 to 500 there are 500 - 5 + 1 = 496 integers, so sum = 1/2 x 496 x (5 + 500) = 125240
How any integers from 1 to 500 are divisible by 7?
71 of them.
If you add all the numbers from 1-500 together what is it?
-499
What is the sum of all integers from 1 to 100?
It's easy to work it out yourself.... Multiply 100 by 49, add 50, add 100 - and you have your answer !
How do you add and subtract positive and negative integers?
+2 + -1= 1
What is 1 through 100?
Usually all the integers (counting numbers) from 1 to 100.Usually all the integers (counting numbers) from 1 to 100.Usually all the integers (counting numbers) from 1 to 100.Usually all the integers (counting numbers) from 1 to 100.
What is the sum of the first 500 numbers?
The sum of the first 500 positive integers is: 1 + 2 + 3 + ... + 498 + 499 + 500 = 125250
How do we add integers?
Integers are whole numbers: 1, 2, 3, and so on. Example: 1 + 1 = 2 (one plus one equals two).
