This is quite simple as first we need to determine how to find the total of all angles in a polygon. Thus, we divide the polygon into triangles. Since every triangle is 180 degrees, and it should contain n - (3 - 1) = n - 2 triangles in a polygon ('n' is the number of sides). Thus, we multiply this by the number of degrees in a triangle (180o). Set to equal 900, and now we have:
900 = 180(n - 2)
Divide by 180, we have:
5 = n - 2
Add 2:
7 = n
Therefore, it is a septagon, a 7 sided figure.
The sum of the angles is 900 degrees - and the polygon does not need to be convex.
9540 degrees
360 degrees (this is true with any convex polygon)
360 degrees
The sum of the interior angles of any polygon of n sides is equal to 180(n - 2) degrees.
360 degrees - and it does not have to be convex.
The sum of the angles is 900 degrees - and the polygon does not need to be convex.
The sum of the exterior angles of ANY polygon, convex or concave, is 360 degrees.
9540 degrees
360 degrees. The sum of the measures of the exterior angles any convex polygon will always be 360 degrees. The formula for finding the sum of the measures of the interior angles is 180(n-2) when n= the total number of sides the polygon has.
360 degrees (this is true with any convex polygon)
360 degrees
The sum of the interior angles of any polygon of n sides is equal to 180(n - 2) degrees.
180(17 - 2) = 2,700 degrees.
The sum of the external angles of ANY convex polygon is 360 degrees. The sum of the internal angles is always equal to 180 (n-2) where n is the number of angles.
No. In a convex polygon, all the internal angles are smaller than 180 degrees.
A convex polygon.