The sum of the numbers from 1 to 60 can be calculated using the formula for the sum of an arithmetic series: ( S_n = \frac{n(n + 1)}{2} ), where ( n ) is the last number in the series. For the numbers 1 to 60, ( n = 60 ). Thus, the sum is ( S_{60} = \frac{60(60 + 1)}{2} = \frac{60 \times 61}{2} = 1830 ). Therefore, the sum of the numbers from 1 to 60 is 1830.
The sum of the first 60 consecutive odd numbers is 3,600.
Their sum is -12
It's 1/10 the sum of all of those numbers.
900
272
The sum of the numbers 1 to 39 = 39 x 40 ÷ 2 = 780 The sum of the numbers 1 to 60 = 60 x 61 ÷ 2 = 1830 Therefore the sum of the numbers 40 to 60 = 1830 - 780 = 1050
60 and 59
The sum of the first 60 consecutive odd numbers is 3,600.
The sum of the first 60 consecutive odd numbers is 3,600.
The sum of the first 60 consecutive odd numbers is 3,600.
The sum of all prime numbers between 60 and 75 is 272
Their sum is -12
It's 1/10 the sum of all of those numbers.
900
60
18 & 42
If the product of the two numbers is the sum times 24, then the product of the two numbers is 2400. 40 times 60 is 2400, and 40 plus 60 is 100. The two numbers are 40 and 60.