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The sum of the polygon's interior angles, if the exterior angle is 45o, is 1080o

The sum of the exterior angles of a polygon is 360o, thus:

exterior_angle x number_of_sides = 360o

⇒ number_of_sides = 360o ÷ exterior_angle

⇒ number_of_sides = 360o ÷ 45o

⇒ number_of_sides = 8.

Interior and exterior angles of a polygon are supplementary, that is add up to 180o, thus:

interior_angle + exterior_angle = 180o

⇒ interior_angle = 180o - exterior_angle

⇒ interior_angle = 180o - 45o

⇒ interior_angle = 135o

Sum of the interior_angles for a regular polygon is:

sum_of_angles = number_of_sides x interior_angle

⇒ sum_of_angles = 8 x 135o

⇒ sum_of_angles = 1080o

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Q: What is the sum of the polygons interior angles measure if the exterior angle of a regular polygon's 45 degree?
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