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What is the sum of the sequence of consecutive whole numbers that begin with 132 and ends with 1780?
Wiki User
∙ 13y ago
There are (1780 - 131) = 1649 numbers on the list.
The one in the middle is 1/2(1780 + 132) = 956.
There are 824 numbers above it, and 824 numbers below it.
Use them to make pairs, like this:
132 + 1780 = 1912
133 + 1779 = 1912
134 + 1779 = 1912
.
.
954 + 958 = 1912
955 + 957 = 1912
Each pair adds to 1912. There are 824 pairs. Their sum is (824) x (1912) = 1,575,488
Don't forget to add the one in the middle: 1,575,488 + 956 = 1,576,444
-- With danken und apologies to Dr. Gauss.
Wiki User
∙ 13y ago
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