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The average of 33 consecutive whole numbers is 58, what is the smallest of these whole numbers? The answer is 42

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Q: The average of 33 consecutive whole numbers is 58 what is the smallest of these whole numbers?

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There is no set of four consecutive whole numbers whose sum is 75.

96 cannot lie between two consecutive whole numbers.

136 cannot lie between two consecutive whole numbers.

The numbers are 746, 747 and 748, as well as 745, 747 and 749 using only consecutive odd whole numbers.

average is 31, but you can't have 4 consecutive whole numbers with this average:29 + 30 + 31 + 32 = 12230 + 31 + 32 + 33 = 126You can have 4 consecutive even numbers: 28 + 30 + 32 + 34 = 124or you can have 29.5 + 30.5 + 31.5 + 32.5 = 124

Related questions

41

If the 33 numbers are consecutive then 58 must have 16 lower and 16 higher so the lowest is 58 - 16 ie 42

54

The average is 58 so, sum(m...n)/33=58. You can think of this as 58 being the middle marker for the consecutive set of numbers which leaves 32 other number, with 16 on one side of 58 and 16 on the other side. So 58-16=42 and 58+16=74. Therefore your consecutive number set is sum(42...74)/33 and so the smallest of these is 42.

8

Consecutive whole numbers have no other whole numbers between them.

There are two consecutive odd, whole numbers. The numbers are 39 and 41.

Divide the sum of the three consecutive numbers by 3: 75/3=25. The smallest of these numbers will be one less than 25 and the largest will be one more than 25, so the three consecutive numbers will be 24, 25, and 26.

21/4 is not a whole number and it cannot be represented as consecutive whole numbers.

Consecutive numbers are whole numbers whose difference is 1.

Consecutive whole numbers will have an odd sum. Consecutive odd numbers, or consecutive prime numbers, will be 29 and 31.

The only two consecutive whole numbers that are prime numbers are 2 and 3. Otherwise, every second consecutive whole number in sequence is even, and being multiples of 2, they cannot be prime.