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Sum of two digits equals 13 but is not divisible by 2?
49, 67, 85
A two digit number is five times the sum of the digits if 9 is added to the number the digits are reversed find the number?
45
The sum of the digits of a certain two-digit number equals the square root of the number What is the number?
81
The sum of digits of a two-digit number if five Find the number if the ten's digit is five more than the one's digit?
50
What four digit number are you are less than 50 x 50 your digits are all odd your digits are all different the sum of your first two digits equals the sum of the last two you are divisible by 5?
Must end in 5 and be less than 2500, so only 1735 fits.
What does the sum of your digits?
The sum of your digits is the total number arrived at after adding two or more numbers.
What is a two digit number that is less than 20. The product of the digits equals half of the sum of the digits?
Eleven 1 + 1 = 2 1 x 1 = 1
The sum of your two digits is the same as the product of your two digits you are a multiple of 11 who am i?
22
What is a prime number that has two digits and the sum of the digits is 14?
13
I am a three digit multiple of 10 I ammore than 600 the sum of my first two digits is 13 the different between my first two digits is 13?
The three-digit number you are describing is 730. It is a multiple of 10, greater than 600, and the sum of the first two digits (7 + 3) equals 10, while the difference (7 - 3) equals 4. However, the criteria provided do not seem to align correctly, as the difference cannot be 13 with the sum being 13. Please clarify the conditions for a correct answer.
What are the last two digits in the sum of factorials of the first 100 positive numbers?
To find the last two digits of the sum of the factorials of the first 100 positive integers, we can observe that for ( n \geq 10 ), ( n! ) ends with at least two zeros due to the factors of 10 in the factorial (from the pairs of 2 and 5). Therefore, we only need to calculate the sum of the factorials from 1! to 9!. The sum ( 1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! + 9! ) equals 40320, and the last two digits are 20. Thus, the last two digits in the sum of factorials of the first 100 positive integers are 20.
What is a number that is prime has 2 digits and the sum of the two digits is 14?
It is: 59
