Their sum is three times the middle number.
The sum of 3 consecutive whole numbers is always equal to 3 times the middle number in that sequence.
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.
-- method -- We need X numbers which are consecutive, so the middle number will be 1/ X of the total. Divide the sum of the numbers by the number of numbers ... in this case divide 186 by 3. The numbers are to be consecutive and even, so subtract 2 from the number go get one of the numbers and add 2 to the number to get the other number. You now have three numbers which are even and consecutive. Now, place a minus sign in front of them, to turn them into negative numbers For instance 12, 14 and 16 are three consecutive numbers whose sum is 42. -12, -14 and - 16 are three consecutive even integers whose sum is -42 Now you know all you need to solve the problem.
The smallest consecutive three numbers that total 120 are... 39, 40 & 41.
Since 57/3 = 19, we know that the middle number has to be 19. The other numbers will be the numbers contiguous to 19. Therefore, the three consecutive numbers which add up to 57 are: 18 + 19 + 20 = 57
Any three consecutive integers are divisible by three because it can be shown that the sum divided by three is the middle number.
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
First find the number which is 1/3 of 51. This is 17. Thus any three numbers which average 17 will always add up to 51. For the numbers to be consecutive and have an average of 17, the middle number must be 17 and the two remaining numbers are 17-1 and 17+1 ie 16 and 18. So the three consecutive numbers are 16, 17 and 18.
The greater number of the three is 26.
Divide 72 by 3, this equals 24. This is the middle of the three numbers, so the answer is 23, 24 and 25. This works with finding any odd amount of consecutive numbers that sum up to another number.
Any two consecutive numbers must comprise one odd and one even number, so their product must be even. Any three consecutive numbers must include two consecutive numbers so the result still applies.
The middle number must be the average, so 681/3 = 227 and the other two numbers are 226 and 228.
The smallest is 55.
The middle number must be one third of 39, ie 13. The other numbers are thus 11 and 15.
If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.
x + x + 1 + x + 2 = 3x + 3 = 3 times the middle number
The answer to that question is 49,50,51
There are no three consecutive numbers with a sum of 170.
No other prime numbers are consecutive because there aren't any other even prime numbers.
The middle number must be one third of 54 ie 18 so the other numbers are 17 and 19.
If the first number is 915, then the second will be 915 + 1 = 916 and the third number will be 915 + 2 = 917. Add 915, 916 and 917 to find the sum. If the question is, what are the three consecutive numbers whose sum is 915, then divide 915 by 3 to find the middle number which is 305. Since the consecutive numbers differ by 1, the numbers are 304, 305, and 306.