EVERY three consecutive numbers add to a multiple of 3:
Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1)
This means that for any three consecutive numbers, the total is 3 times the middle number.
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
This is no set of three consecutive numbers that when multiplied equal 387.
71,72,73 :)
Do you mean:"What three consecutive numbers add up to 99?" If you do, then the numbers are 32, 33, 34.
nine, ten and eleven. Three consecutive numbers that total thirty
If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
A multiple of 3 Also a multiple of 6.
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
There are no three consecutive numbers with a sum of 170.
There are no sets of three consecutive numbers totaling 118.
19, 20, 21
79
Can't be done. The number has to be a multiple of 3.
There are no three consecutive numbers that are squares. Otherwise, there are an infinite sets of squares of three consecutive numbers: for example, {1,4,9}, or {4,9,16} or {576, 625, 676}
This is no set of three consecutive numbers that when multiplied equal 387.
Any three-digit multiple of 60, from 120 to 960, has the first five counting numbers as factors.