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Let r be the radius of the (base)ball.

The surface area of a sphere = 4 * pi * r ^2

Therefore, the surface area of an ideal (base)ball = 4 * 3.14159 * 1.475^2 [in^2] = 27.34 [in^2]

Note that I don't like to use the term Baseball, because a baseball is not an ideal sphere. A baseball has markings and asperities. A perfect sphere does not.

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14y ago
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Q: What is the surface area of a baseball with a radius of 1.475 inches?
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