Let r be the radius of the (base)ball.
The surface area of a sphere = 4 * pi * r ^2
Therefore, the surface area of an ideal (base)ball = 4 * 3.14159 * 1.475^2 [in^2] = 27.34 [in^2]
Note that I don't like to use the term Baseball, because a baseball is not an ideal sphere. A baseball has markings and asperities. A perfect sphere does not.
The factors of 1475 are: 1, 5, 25, 59, 295, 1475
3.9% of 1475 is the same as .039 x 1475 = 57.525
1475 = 52*59
1475 sqare metres = 15,876.8 sqare feet
1500 - 25 = 1475
The factors of 1475 are: 1, 5, 25, 59, 295, 1475
1475 was the 14th century,
3.9% of 1475 is the same as .039 x 1475 = 57.525
1475 + 7100 = 8575
1475 = 52*59
The number 1475 written in Roman numerals is MCDLXXV
1475 sqare metres = 15,876.8 sqare feet
no
1 x 1475, 5 x 295, 25 x 59
If you supply it with 1475 Watts (1475 Joules per second) then there will be 1475 Watts of heat. A tiny fraction will be conducted away through the component parts that support the heater and supply the power, so most is put out as radiated or convected heat
1475
1475