552 square inches.
The surface area of a cylinder with height of 12 inches and 7 inch radius is 835.66 square inches
384 inches squared
That is 6 times the area of a single square of 12 x 12.
The box has 6 sides. 2 each of 8 x 9, 8 x 12 and 9 x 12 ie 2 x (72 + 96 + 108) ie 2 x 276 which is 552 sq ins.
864 inches2
Lets say its 12 inches by 5 inches by 10 inches It will be 12X5 = 60X10 =600square inches.
2x((15*12)+(15*10)+(12*10)) is 2*(180+150+120) = 900in2
The surface area of a cylinder that has a radius of 6 inches and a height of 12 inches is 678.58 square inches.
The surface area of a cylinder with height of 12 inches and 7 inch radius is 835.66 square inches
"each side is 10 12 inches" Unsure about how this is worded, however: To find the area of a cube, you must multiply the area of one face, by its length. The surface area for a cubic box with 10" sides would be 10x10x10 = 1000 For a box of 12" sides, this would be 12x12x12 = 1452
864 square inches.
34sq in
Assuming that the box is a rectangular parallelepiped, it has two sides each with dimensions 2*3, 2*4, and 3*4, with areas of 6, 8, and 12 square inches respectively. The total surface area therefore is 2(6 + 8 + 12) = 52 square inches.
- Area of the bottom = (12 x 7) = 94 square inches. Area of the top = same as the bottom. - Area of the right side = (12 x 6) = 72 square inches. Area of left side = same as right side. - Area of the front end = (7 x 6) = 42 square inches. Area of the back end = same as the front end. Simply add these up.
Total surface area = 2*(12*8 + 8*3 + 3*12) = 312 square inches.Total surface area = 2*(12*8 + 8*3 + 3*12) = 312 square inches.Total surface area = 2*(12*8 + 8*3 + 3*12) = 312 square inches.Total surface area = 2*(12*8 + 8*3 + 3*12) = 312 square inches.
384 inches squared
That is 6 times the area of a single square of 12 x 12.