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2*pi*r*h+2*pi*r2=2*pi*5*8+2*pi*52 = 130pi

Which is approx

408.40704......

The surface area of each of the two ends is pir2.

The surface area of the curved surface is 2pirh.

pi = 3.1416

r = 5

h = 8

Plug the values into the formulas.

Each end surface area = 3.1416 X 52

= 78.54

Area of both of the two ends combined = 78.54 X 2 = 157.08

Curved surface area = 2 X 3.1416 X 5 X 8 = 251.328

Add the ends surface areas and curved surface area

157.08 + 251.328 = 408 rounded to the nearest whole number.

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Q: What is the surface area of a cylinder with a radius of 5 and a height of 8?
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