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What is the surface area of a right angle triagular prism whose height is in the ratio of 15 to 8 to its width and has a length of 20 cm with a volume of 6075 cubic cm showing work done?
Wiki User
∙ 10y ago
1 Let the height and width be 15x and 8x respectively
2 So: 0.5*15x*8x*20 = 6075 or 1200x2 = 6075 cubic cm
3 Divide both sides by 1200 and then square root both sides
4 So: x = 2.25 then height 15*2.25 = 33.75 cm and width 8*2.25 = 18 cm
5 Hypotenuse: 17*2.25 = 38.25 cm because it's part of a Pythagorean triple
6 Surface area:(2*0.5*18*33.75)+(20*33.75)+(20*18)+(20*38.25) = 2407 square cm
7 Check: 0.5*18*33.75*20 = 6075 cubic cm
Wiki User
∙ 10y ago
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