First find the radius by making it the subject of 4/3*pi*radius3 = volume
Radius = cube root of (82.458648*3/4*3.142) = 2.7cm
Surface area = 4*3.142*2.72 = 91.62072 square cm
This is due to the distortions caused by taking a 3 dimensional sphere and converting it to a 2 dimensional layout.
If: area = 4*3.142*radius2 = 153.958 sq cm Then: radius = sq rt of (153.958 divided by 4*3.142 = 3.5 cm Hence: volume = 4/3*3.142*3.53 = 179.6176667 cubic cm
No. You obviously misuderstand the concept of a "curved" universe, probably imagining it like the 2-D surface on a 3-D sphere. This actually isn't too bad of a way to view it, but it has its problems -- caused mainly by taking the mathematical analogy too far. A Friedmann Universe -- ie, one like the one we're now in -- can be mathematically curved but without a surface, and without any other dimension into which this curvature is (well) curving. Even in a universe that was 2-D and closed (ie, a sphere), and its mass was constrained to the surface of a sphere, then no force would be needed to keep that mass on the surface. That mass could no more leave the surface of the sphere then you could walk outside of the three spatial dimensions of our Universe.
Since there are a total of 24 time zones, then taking the Earth as a perfect sphere of 360o's, then each time zone covers 15o's of the Earth's surface.
The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".See link for an illustration.The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".See link for an illustration.The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".See link for an illustration.The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".See link for an illustration.
The formula for the surface area of a sphere is 4πr² and the formula for the volume is (4/3)πr³, where r is the radius of the sphere. Setting 4πr² equal to 588 and (4/3)πr³ equal to 1372, you can solve for the radius by equating the two expressions and taking the cube root of the result. Once you have the radius, you can calculate the surface area using the formula and divide it by the volume to find the ratio.
Radius = 23.565/(2*3.142) = 3.75 inches Volume = 4/3*3.142*3.753 = 220.921875 cubic inches Surface area = 4*3.142*3.752 = 176.7375 square inches
showing the people you have real money, that means taking it out of your merse (man purse) and showing it to them.
S.A. = 4 pi r^2 Substituting 314 = 43.14r^2 Algebraically rearrange 100/4] r^2 = 314 / (4 * 3.14) r = sqrt[314/(4*3.14)] r = sqrt[ 100/4] r = sqrt[25] r = 5 inches The circumference of a sphere is a circle. Hence C = 2 pi r C = 23.145 C = 10*3.14 C = 31.4 inches.
taking or showing extreme care about minute details
sublimation!! :)
it means ur taking it to the next level or his just showing off