The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.
The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".
See link for an illustration.
The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.
The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".
See link for an illustration.
The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.
The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".
See link for an illustration.
The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.
The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".
See link for an illustration.
Chat with our AI personalities
The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.
The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".
See link for an illustration.
Yes they are made out of 12 curved shapes (ellipses) called gores.
Depends on the information that you DO have. Half the diameter is the easiest formula, but that only works if you know the diameter.
The radius of a sphere is equal distance from the center of the sphere to all points within the sphere.
Didn't know it was lost! To find the radius of a sphere you first need to know what information you do have. If none, then the easiest way is to measure the volume using water displacement. Then V = 4/3*pi*r3 so that r = cube root of 3V/4pi The diameter is not that easy to measure because it is the distance between two parallel tangential planes to the sphere. It is very difficult to ensure that the planes are truly parallel.
Sphere is one syllable: sphere.