The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.
The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".
See link for an illustration.
The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.
The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".
See link for an illustration.
The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.
The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".
See link for an illustration.
The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.
The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".
See link for an illustration.
The net consists of a series of vertical lenticular (lens-shaped) sections that are joined together at their middle.
The lenticular sections are flattened slices of the surface of the sphere from "north pole" to "south pole", taking in a few longitudes each, joined together along the "equator".
See link for an illustration.
Yes they are made out of 12 curved shapes (ellipses) called gores.
Depends on the information that you DO have. Half the diameter is the easiest formula, but that only works if you know the diameter.
The radius of a sphere is equal distance from the center of the sphere to all points within the sphere.
Sphere is one syllable: sphere.
Didn't know it was lost! To find the radius of a sphere you first need to know what information you do have. If none, then the easiest way is to measure the volume using water displacement. Then V = 4/3*pi*r3 so that r = cube root of 3V/4pi The diameter is not that easy to measure because it is the distance between two parallel tangential planes to the sphere. It is very difficult to ensure that the planes are truly parallel.
no
Yes because the surface area of a sphere is 4*pi*radius squared
The net static electric charge on the metal sphere would be +3 elementary charges. This means the sphere has an excess of 3 positive charges.
It depends on the figure. For example, you cannot draw a net for a sphere, an ellisoid or a torus.
The electric field inside a charged hollow sphere is zero because the net contribution from the charges on the inner surface of the sphere cancels out due to symmetry. This means that the field created by the positive charges is equal and opposite to the field created by the negative charges, resulting in a net field of zero inside the sphere.
Since a sphere has an infinite number of side and angles, we can easily conclude that the new drawing for a sphere is a simple circle. The other new drawings do not have an infinite number of sides. Hence, They look 3D
Yes they are made out of 12 curved shapes (ellipses) called gores.
Depends on the information that you DO have. Half the diameter is the easiest formula, but that only works if you know the diameter.
Zero, because the electric field inside a charged hollow sphere is zero. This is due to the Gauss's law and symmetry of the charged hollow sphere, which results in no net electric field inside the sphere.
The gravitational force inside a solid sphere is zero because the gravitational forces from the parts of the sphere above cancel out the forces from the parts below, resulting in a net force of zero at any point inside the sphere. This is known as the shell theorem.
A tennis ball is a spherical shape. Surface area of a sphere in square units = 4*pi*radius2 Volume of a sphere in cubic units = 4/3*pi*radius3
When fully submerged on earth, yes. The net buoyancy force will be equal to the weight of the water displaced minus the weight of the object doing the displacing. Because the volume of water displaced by the water will be the same, and presumably have the same weight when the objects are both fully submerged, and the sphere of empty vacuum weighs less than the sphere of air, there will be a greater net upward buoyancy force on each object on earth.