18 and 24 x^2 - 42x + 432 = 0 (x - 18)(x - 24) = 0 x = 18 and x = 24 Why? x + y = 42 xy = 432 y = 432/x x + 432/x = 42 X^2 + 432 = 42x x^2 - 42x + 432 = 0If two numbers have a sum of 42 and a product of 432, the two numbers are 18 and 24.
if x-42x-8=0 x=-5.12500
y-42x = 24 >> Add 42x to both sides << y=24+42x >> Subtract 24 from both sides << y-24=42x >> Divine both sides by 42 << x=(y-24)/42
−39x−6
5x - 42x + 5 = - 37 x +5
42x+35x-35x=42x it's leave 85 so it's change into a negative 42x-85 is the answer
If you mean: -2(3x-3) = 7x-2 then the value of x works out as 8/13
x2 - 42x + 441 = (x - 21)2
126
If that's +42x + 49, the answer is (3x + 7)(3x + 7) or (3x + 7)2 If that's -42x + 49, the answer is (3x - 7)(3x - 7) or (3x - 7)2
210x
126 ._.