cant answer this question without more information....probability requires a ratio.
100%
it depends how many blue marbles there are and how many marbles total.
1/3 or 33%
The answer depends on how many blue and non-blue marbles there are, whether the choice is random and how many marbles are chosen. There is no information provided on any of these.
We will assume that the bag contains 11 marbles (this is not a trick question!), so 4 are blue and 7 are not blue, so the probability of a color other than blue is 7/11.
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
if there is a jar containing 5 red marbles 6green and 4 blue what is the probability off not chossing a blue marble
It can not be determined with the data provided.
100%
it depends how many blue marbles there are and how many marbles total.
This is the same as the probability of choosing either a red of a blue marble. There are 5+4 out of 15 ways of doing this. The probability is therefore 9/15 = 3/5.
1/3 or 33%
5:16
The answer depends on how many blue and non-blue marbles there are, whether the choice is random and how many marbles are chosen. There is no information provided on any of these.
We will assume that the bag contains 11 marbles (this is not a trick question!), so 4 are blue and 7 are not blue, so the probability of a color other than blue is 7/11.
The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.
25