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2.01 seconds.
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∙ 9y ago
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What is the length of a pendulum whose period on the moon matches the period of a 1.94-m-long pendulum on the earth?
Nice problem! I get 32.1 centimeters.
What is the length in inches of a simple pendulum whose period s 1 s?
9.5 inches
How do you write an algebraic expression from a real world situation?
2*pi*sqrt(L/g) this expression gives (approximately) the period (in seconds) of a pendulum whose length is L (metres) and g is the acceleration due to gravity = 9.8 metres/second2.
What is the side of a square whose perimeter is 100cm?
25=side
What is the length of a rectangle whose width is 4 and area of 90?
length: 22.5
What is the length of a pendulum whose period on the moon matches the period of a 1.94-m-long pendulum on the earth?
Nice problem! I get 32.1 centimeters.
What is the length in inches of a simple pendulum whose period s 1 s?
9.5 inches
What is pendulum length?
A pendulum whose period is precisely two seconds, one second for a swing forward and one second for a swing back, has a length of 0.994 m or 39.1 inches.
What is the area of a square whose side is 100cm in lenght?
Area = length x width Area = 100cm x 100cm Area = 10000cm2
What is the area of a square whose side is 100cm in length?
The area of a square is the length of a side squared (multiplied by itself)A square that have 100 cm on all sides is 100cm*100cm = 10,000 cm2
If the length of a pendulum is increased by 4 times whose time period is 2 sec what will happen to the time period?
the longer you make the pendulum arm the longer it will take to perform its swing,the same thing would happen if you only increased the weight on the end of the arm.
What is the period of a pedelum?
The period of oscillation of a simple pendulum displaced by a small angle is: T = (2*PI) * SquareRoot(L/g) where T is the period in seconds, L is the length of the string, and g is the gravitional field strength = 9.81 N/Kg. This equation is for a simple pendulum only. A simple pendulum is an idealised pendulum consisting of a point mass at the end of an inextensible, massless, frictionless string. You can use the simple pendulum model for any pendulum whose bob mass is much geater than the length of the string. For a physical (or real) pendulum: T = (2*PI) * SquareRoot( I/(mgr) ) where I is the moment of inertia, m is the mass of the centre of mass, g is the gravitational field strength and r is distance to the pivot from the centre of mass. This equation is for a pendulum whose mass is distributed not just at the bob, but throughout the pendulum. For example, a swinging plank of wood. If the pendulum resembles a point mass on the end of a string, then use the first equation.
How do you write an algebraic expression from a real world situation?
2*pi*sqrt(L/g) this expression gives (approximately) the period (in seconds) of a pendulum whose length is L (metres) and g is the acceleration due to gravity = 9.8 metres/second2.
What is the side of a square whose perimeter is 100cm?
25=side
What is a perimeter of a square whose area is 625cm square?
The perimeter is 100cm
What is the lent of a quadrilateral whose area is 100cm and perimeter is 40cm?
It is a square with lengths of 10 cm
How many meters tall is person whose height is 175 cm?
175cm *1m/100cm =1.75m
