Total of interior angles is: (Number of sides)*180° - 360° = 9*180° - 360° = 1260°
The sum of the interior angles is (9-2)*180 = 7*180 = 1260 degrees.
Exterior angles are 360 degrees Interior angles are 1260 degrees
Each interior angle measures 140 degrees.
The answer is 7pi radians, or 7*180° = 1260° (N-2)pi radians, or (N-2)*180° N is the number of sides on the polygon; Sum of interior angles formula
Imagine connecting all the vertices of the regular 9-gon to the centre of the 9-gon. We have now created 9 triangles, so the sum of all their interior angles is 9*180 degrees = 1620 degrees. Notice that the sum of these angles is exactly the sum of the interior angles of the 9-gon, except we have created extra angles around the centre point. These extra make a circle, so they must add up to 360 degrees. Therefore is we substract 360 degrees from 1620 degrees we get the sum of all the interior angles of a regular 9-gon: 1620 degrees - 360 degrees = 1260 degrees. So finally, since there are 9 vertices, every single vertex must have an interior angle of 1260 degrees / 9 = 140 degrees.
A 9-gon is a polygon with nine sides and nine angles
Sum of degrees of angles in a n-gon = (n-2)*180 degrees, where n = sides nona- = 9 sides, so n = 9 (9-2)*180 degrees = 1260 degrees. 1260 degrees total/9 sides = 140 degrees per side
Presumably the question concerns a hendecagon. The sum of the interior angles of a n-gon are (n-2)*180 degrees. For a hendecagon, the sum of the interior angles would be 9*180 = 1620 degrees. If the hendecagon is regular, then all its interior angles are equal, and each is then 1620/11 = 147.2727.. degrees.
5
1260 degrees
The total interior angles add up to 1260 degrees.
Sum of exterior angles = 360 degrees So there are 360/40 = 9 angles. Exterior angle = 40 deg so interior angle = 180 - 40 = 140 deg Nine angles, 140 deg each = 140*9 = 1260 degrees. Alternatively, once you know it is a nonagon (9-gon), sum of interior angles = (9-2)*180 = 7*180 = 1260 degrees.