1,400
294/0.6 = 490 Therefore, the number that 294 is 60 percent of is 490.
The relative atomic mass of ununoctium is estimated as 294.
No.
We must ascertain whether 294 contains factors other than 1 and itself in order to classify it as a prime or composite number. To start, we can see if it can be divided by any prime integer smaller than its square root, or roughly 17. As we examine the prime numbers that are smaller than 17: 294 ÷ 2 = 147 (a non-integer) 294 ÷ 3 = 98 (a non-integer) 58.8 (not a whole number) = 294 ÷ 5 42 (a whole number) = 294 ÷ 7 Thus, 294 divides by 7. Given that 294 divides evenly by 7, it has factors besides 1. 294 is a composite number as a result.
Yes, 294 is even, therefore it is non-prime.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 294 is an even number.
An atom's atomic number corresponds to the number of protons in its nucleus, so an element with an atomic number of 117 has 117 protons. Since the atomic mass is 294, which accounts for the total number of protons and neutrons in the nucleus, we can subtract the atomic number from the atomic mass to find the number of neutrons: 294 (atomic mass) - 117 (atomic number) = 177 neutrons. Therefore, an atom of element 117 with an atomic mass of 294 would have 117 protons and 177 neutrons, resulting in 117 neutral atoms.
2 x 3 x 7 x 7 = 294
2 x 3 x 7 x 7 = 294
Yes.
The (12) factors of 294 are: 1, 2, 3, 6, 7, 14, 21, 42, 49, 98, 147, 294
You'll find the answer in a 'trial and error' way. The equation is basically x³-x²=294 All you have to do is replace the x with one number. The answer is 7³-7²=294