Two, heads or tails.
The number of combinations - not to be confused with the number of permutations - is 2*21 = 42.
You have 6 choices of cards, two possibilities with the coin and 6 numbers on the cube. The number of combinations is : 6 x 2 x 6 = 72.
The total number of 1-bit combinations is 2. This is because a single bit can have two possible values: 0 or 1. Therefore, the combinations are {0, 1}.
To determine the number of leaves on a tree diagram representing all possible combinations of tossing a coin and drawing a card from a standard deck of cards, we first note that there are 2 possible outcomes when tossing a coin (heads or tails) and 52 possible outcomes when drawing a card. Therefore, the total number of combinations is 2 (coin outcomes) multiplied by 52 (card outcomes), resulting in 104 leaves on the tree diagram.
2 to the 7th power = 128 * * * * * No. That is the total number of combinations, consisting of any number of elements. The number of 2 number combinations is 7*6/2 = 21
To represent all possible combinations of tossing a coin and drawing a card from a standard deck, you need to consider both events. Tossing a coin has 2 outcomes (heads or tails), and drawing a card from a standard deck has 52 outcomes. Therefore, the total number of combinations is 2 (coin outcomes) multiplied by 52 (card outcomes), resulting in 104 leaves on the tree diagram.
There are 72 permutations of two dice and one coin.
18 different combinations. When a coin is tossed twice there are four possible outcomes, (H,H), (H,T), (T,H) and (T,T) considering the order in which they appear (first or second). But if we are talking of combinations of the two individual events, then the order in which they come out is not considered. So for this case the number of combinations is three: (H,H), (H,T) and (T,T). For the case of tossing a die once there are six possible events. The number of different combinations when tossing a coin twice and a die once is: 3x6 = 18 different combinations.
7878
What a load of s**t is your most common answer
48
The number of combinations of five numbers depends on the total number of available numbers to choose from, as well as whether the order of selection matters. If you have a specific set of numbers (for example, 1 to n), you can calculate the combinations using the formula for combinations: ( \binom{n}{r} = \frac{n!}{r!(n-r)!} ), where ( n ) is the total number of numbers and ( r ) is the number of selections (in this case, 5). If no total is specified, the answer cannot be determined.