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I presume you meant 2^n (2 raised to the nth power), not 2*n (2 times n). That's answers.com's character set problem again (I trust, giving you the benefit of the doubt). The answer is that for each of the n elements, it is either in any particular subset or it isn't. Which elements are in and which are not in a subset defines the subset. So for example, if n is 3, say a, b, and c, there are 2 sub-collections of the set of all subsets: those containing a and those not containing a. In each of those sub-collections, there are 2 sub-collections based on whether they contain b, for a total of 4 (2*2) sub-collections. Finally, of each of these 4, there are 2 subsets: those containing c and those not containing c, for a total of 8 (2*2*2 or 2^3) subsets. Got it?
Let the numbers be A,B and C and assume that A ≠ B ≠ C 1) Subtract B from A. If the result is a positive number then A > B otherwise B > A. 2) Subtract the greater of A and B from C. If the result is a positive number then C is the largest number otherwise the subtrahend (either A or B) is the largest number.
i don't know the formula but it is if the formula was for instance a,b,c,d,e,f that could be one subset but f,e,d,c,b,a couldn't be because you have to picture them like floating numbers in a circle they can be in any order so all of the combomatins of a,b,c,d,e,f are just one but theen you have to count b,c,d,e,f as on and so on and so forth there are about....... under100 or over 700 figure it out!
If any number B is subtracted from a number A to give C, then C+B =A If A - B = C then B+C = A Eg 7 - 2 = 5 Hence 2 + 5 = 7
No
{a,b,c,d} {a,b} {a,c} {a,d} {b,c} {b,d} {c,d}
If B and C are the components of the mixture the total number of molecules is identical.
Cardinality is simply the number of elements of a given set. You can use the cardinality of a set to determine which elements will go into the subset. Every element in the subset must come from the cardinality of the original set. For example, a set may contain {a,b,c,d} which makes the cardinality 4. You can choose any of those elements to form a subset. Examples of subsets may be {a,c} {a, b, c} etc.
c(6,5)
It is 31504.
Let the number be X, then B% = B/100 → B% of X = C → B/100 x X = C → X = C ÷ (B/100) = C x 100/B = 100C ÷ B So to find the number, divide C by B percent.
I presume you meant 2^n (2 raised to the nth power), not 2*n (2 times n). That's answers.com's character set problem again (I trust, giving you the benefit of the doubt). The answer is that for each of the n elements, it is either in any particular subset or it isn't. Which elements are in and which are not in a subset defines the subset. So for example, if n is 3, say a, b, and c, there are 2 sub-collections of the set of all subsets: those containing a and those not containing a. In each of those sub-collections, there are 2 sub-collections based on whether they contain b, for a total of 4 (2*2) sub-collections. Finally, of each of these 4, there are 2 subsets: those containing c and those not containing c, for a total of 8 (2*2*2 or 2^3) subsets. Got it?
If your 7 element set is {a, b, c, d, e, f, g}, you would list a 3 element subset by taking any 3 elements of the set eg., {a, d, g} or {b, c, f}, etc. To count all of the subsets, the formula is 7C3, where 7C3 is 7!/(3!*4!), or 35 different unique 3 element subsets of a 7 element set.
There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.There are an infinite number of combinations for A, B, and C in this case. Just assign any number for A and for B, then calculate the value for C.
for the largest number: #include<stdio.h> void main() { int a,b,c,number,largestnumber; a=99; b=9; c=77; if(a>b) { number=a; } else if(b>c) { number=b; } else { number=c; } largestnumber=number; printf("%d",largestnumber); }
Let the numbers be A,B and C and assume that A ≠ B ≠ C 1) Subtract B from A. If the result is a positive number then A > B otherwise B > A. 2) Subtract the greater of A and B from C. If the result is a positive number then C is the largest number otherwise the subtrahend (either A or B) is the largest number.