You have enough fingers and toes to figure this one out (unless you are a redneck which might explain the question in the first place). The answer should also be memorized: 15. Please don't make a mockery of the calculus section.
7 × (r + 8) = 7(r + 8) = 7r + 56
To determine how many times 8 goes into 63, you would perform long division. When you divide 63 by 8, you get 7 with a remainder of 7. This means that 8 goes into 63 a total of 7 times, with a remainder of 7.
The total is 8(1/4 + 3/4 = 1 + 7 = 8 )
7 columns * 8 rows = 56 units
7 quadrilaterals = 7 x 4 = 28 sides 8 hexagons = 8 x 6 = 48 sides Total is 76 sides
1
7 goes into 56 8 times56 / 7 = 8
7 pairs but a total of 8 C1 - C8
about 7 to 8 tons
To calculate the number of 7-number combinations from 8 numbers, you can use the combination formula, which is nCr = n! / r!(n-r)!. In this case, n = 8 (total numbers) and r = 7 (numbers chosen). Plugging these values into the formula, you get 8C7 = 8! / 7!(8-7)! = 8 ways. Therefore, there are 8 different combinations of 7 numbers that can be chosen from a set of 8 numbers.
Seven can go into fifty-six a total of eight times, since (56 \div 7 = 8). This means that if you multiply 7 by 8, you get 56.
She probably have 7 or 8 awards so far!!!!:)