138.48
The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.
It depends on the dimensions of the base and the height (slant or vertical) of the pyramid.
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Base times Height divided by three. The base is perpendicular to the height, which ends at the highest point of the pyramid. To find the area of the base, one simply uses 2-dimensional geometry. Triangle: Base of triangle times height of triangle over 2 Any regular polygon: Apothem (perpendicular distance from orthocenter to a side) times perimeter divided by 2.
It is 9180900 square inches.
if you know the height and the apothem, use pythagorean theorem to solve for it.
Calculate the area of the 5 individual triangles that make the pyramid and the area of the pentagonal base and add these six areas together. Atriangle = 1/3 Base x Height Apentagon = (Perimeter x Apothem)/2 Apothem = side length/(2Tan(∏/Number of sides))
144
V = (1/3) (area of the base) (height) Area of a pentagon = 1/2 x apothem length x 5 x length of a side of the pentagonthe apothem is the perpendicular distance from the center of the pentagon to the side of the pentagon
The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.
It depends on the dimensions of the base and the height (slant or vertical) of the pyramid.
The answer depends on what you wish to work out: the angles, height, surface area, volume. Also, you need more information: the vertical or inclined height and whether or not the pyramid is a right pyramid.
SA = 3as + 3sl a = apothem length (length from center of base to center of one of the edges). s = length of a side l = slant height
Squares do not have a surface area. They simply have an area. This square's area is 144m^2
It has to do with the surface area formula: To find the total surface area of a pyramid, use this equation: Surface Area = B + 1/2 * P * s B = base area P = perimeter of the base s = slant height To find the volume of a Pyramid, substitute into this equation: V=1/3Bh B=base area h=height of pyramid
To calculate the surface area of a truncated pyramid, you first take the surface area of each side. That would be the base time the straight height. If it is a 4 side pyramid with equivelant sides, multiply that answer by 4.
120