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Q: What is the surface area of a square pyramid when 4 is the side length and 13 as the slant height?
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Related questions

What is the lateral surface area of this square pyramid that has a base length of 4 centimeters and a slant height of 9 centimeters?

72 cm square.


What is the total surface area of a square pyramid with an apothem of 8 and a height of 8.54 and the squares length and width of 6?

138.48


What is the surface area of the right square pyramid in square meters?

It depends on the dimensions of the base and the height (slant or vertical) of the pyramid.


Formula for surface area of a pyramid?

The surface area is length times width plus length. Then you find the square root of the width divided by two and then squared. You add this to the height squared plus the width. The width is multiplied by the square root of 1/2 squared plus the height squared.


What is the formula for the surface area of a square pyramid?

Call the length of the base s and the slant height of one triangle l SA = s2 + 2sl


What is the surface area of a box that is 7.75x5.5x10.75?

Surface area = 2*(length*width + width+height + height*length) = 370.125 square units.


How do you find lateral area of a square pyramid?

You need some information about the height of the pyramid and the formula will depend on whether you have the vertical height or the slant height or the length of a lateral edge.


What is the volume of a square pyramid with a base side length of 7 and a height of 9?

42.7


What is the volume of a square pyramid with length of 12Cm and a height of 20Cm?

Volume = 960 cm3


What is the slant height of a pyramid that has all sides as equilateral triangles with sides of length of 9 cm and the surface area of the pyramid is 140.4 square cm?

The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.


The pyramid shown has a square base that is 1818 inches on each side. The slant height is 1616 inches. What is the surface area of the pyramid?

It is 9180900 square inches.


How do you find the height of a cone if you have the slant height and the diameter?

The height would be The square root of the square of the slant surface length minus the square of the radius of the cone at the base.