Q: What is the total value of the digit 648?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

648

-- The first digit can be any one of nine. (It can't be zero).-- The second digit can be any one of nine. (Anything except the one you used for the first digit.)-- The third digit can be any one of eight. (Anything except the two already used.)Total possibilities = (9 x 9 x 8) = 648

-123456786

There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.

Since there is no bold digit, there is no place value!Since there is no bold digit, there is no place value!Since there is no bold digit, there is no place value!Since there is no bold digit, there is no place value!

Related questions

648

numbers between 100 and 1000 = 900 numbers between 100 and 1000 which do not have digit 6 in any place = 8 x 9 x 9 = 648 Unit digit could take any value of the 9 values (0 to 9, except 6) Tens Digit could take any value of the 9 values (0 to 9, except 6) Hundreds digit could take any value of the 8 values (1 to 9, except 6) numbers between 100 and 1000 which have atleast one digit as 6 = 900 - 648 = 252

To find 72% of 900 ml, you can multiply 900 by 0.72 (which is the decimal equivalent of 72%). Value = Percentage × Base Value=Percentage×Base Value = 0.72 × 900 Value=0.72×900 Value = 648 ml Value=648ml So, 72% of 900 ml is 648 ml.

648

These numbers are selections from the numbers from 100 to 999. That's 9 choices for the first digit. Each time, the second digit has 9 choices (0 to 9 excluding the hundreds digit), and then the last digit has 8 choices. Total is then 9x9x8 = 648

-- The first digit can be any one of nine. (It can't be zero).-- The second digit can be any one of nine. (Anything except the one you used for the first digit.)-- The third digit can be any one of eight. (Anything except the two already used.)Total possibilities = (9 x 9 x 8) = 648

A three digit number can be chosen in 9*10*10 = 900ways No. of ways to choose a three digit number without 7 is 8*9*9 = 648 ways probability of picking a three digit number that includes atleast one digit that is 7 is 1- (648/900) = 252/900 = 7/25

-123456786

There are a total of 900 3-digt numbers (100 thru 999); Of these there are 9x9x8 = 648 numbers that do not contain repeating digits (first position: 9 possibilities, second place 9 possibilities; the 10 digits minus the one used in the first place. and third place 8 possibilities; 10 digits minus the two used in the first and second places) So, there should be 900-648=252 3-digit numbers with at least one repeating digit.

WHAT IS THE VALUE OF THE DIGIT 9 IN 4,729 ?

To round to the nearest hundred, look at the tens digit - if it is 4 or less, round down otherwise it is 5 or more and so round up: In 648, the tens digit is 4 (which is 4 or less) so round down to 600.

The first digit can be any one of 9. (any digit except zero)For each of these . . .The second digit can be any one of 9. (any digit except whatever the first one is)For each of these . . .The third digit can be any one of 8. (any digit except whatever the first 2 are)Total possibilities = 9 x 9 x 8 = 648