There are a total of 900 3-digt numbers (100 thru 999);
Of these there are 9x9x8 = 648 numbers that do not contain
repeating digits (first position: 9 possibilities, second place 9 possibilities;
the 10 digits minus the one used in the first place. and third place 8 possibilities;
10 digits minus the two used in the first and second places)
So, there should be 900-648=252 3-digit numbers with
at least one repeating digit.
823543
720 (10*9*8)
625 if numbers can have leading 0s, 500 otherwise.
81
9x9x8x7x6x5 = 81x56x30 = 136080
757
823543
720 (10*9*8)
625 if numbers can have leading 0s, 500 otherwise.
9x9x8x7x6x5x4x3 =1632960
There are 5! = 120 such numbers.
81
9x9x8x7x6x5 = 81x56x30 = 136080
There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.
162
27 three digit numbers from the digits 3, 5, 7 including repetitions.
738 numbers