In case of 1s order Splitting above answer is correct. in case of Non-1st Order splitting we should follow the following example
let for AMX(Quartet)
take our hand fingers for spectrum explanation(vomit thumb finger), distance between little finger to middle finger let it 'X' minus distance between showing finger and side finger of little finger let it 'y'.
Now the coupling constant is (X-Y)/2.
Kindly suggest if any mistake or difficulty to understand.
No, it is not true.
True
Yes this is true
Kinematics does not require constant acceleration. There are different equations for different situations. So some of the equations will be valid even when the acceleration is not constant.
It is something that is proven as true and indisputable.
In a theoretical scenario with constant velocity, the true acceleration would typically be zero.
Change cannot be a constant, constant means unchanging. it is a catch 22+1Answers.comAnswers.comIt used to be true. But guess what happened?
yes. that is very true
A constant that multiplies a variable is no longer a constant. By its very definition, a constant is something that can never be different. The result of variable multiplication is thus a variable, not a constant.I would say that the above answer is not necessarily true. The common equation for the area of a circle is: area = pi * r2The fact that you are multiplying the mathematical constant pi by a variable does not change the value of pi.Agree with the second answer. Jsut to add, a constant that multplies a variable is called a coefficient.
independent variable
True
true!
No, it is not true.
Yes they are true in a Dictionary.
TRUE
True
True.