The 90th term of the arithmetic sequence is 461
It is an arithmetic sequence if you can establish that the difference between any term in the sequence and the one before it has a constant value.
An arithmetic sequence
The nth term of an arithmetic sequence = a + [(n - 1) X d]
Arithmetic- the number increases by 10 every term.
In an arithmetic sequence the same number (positive or negative) is added to each term to get to the next term.In a geometric sequence the same number (positive or negative) is multiplied into each term to get to the next term.A geometric sequence uses multiplicative and divisive formulas while an arithmetic uses additive and subtractive formulas.
The one number, 491419 does not constitute a sequence!
One number, such as 7101316 does not define a sequence.
A term in math usually refers to a # in a arithmetic/geometric sequence
What your tutor wants is for you to identify the factors of 21 and of 56. From this information you will find it easy to answer the question. good luck
It is a + 8d where a is the first term and d is the common difference.
i dont get it
Because that is how it is defined and derived.
It is the sequence of first differences. If these are all the same (but not 0), then the original sequence is a linear arithmetic sequence. That is, a sequence whose nth term is of the form t(n) = an + b
The constant increment.
It is: 0.37*term+0.5
A sequence where a particular number is added to or subtracted from any term of the sequence to obtain the next term in the sequence. It is often call arithmetic progression, and therefore often written as A.P. An example would be: 2, 4, 6, 8, 10, ... In this sequence 2 is added to each term to obtain the next term.
It appears that a number of -79 is missing in the sequence and so if you meant -58 -65 -72 -79 -86 then the nth term is -7n-51 which makes 6th term in the sequence -93
The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
The sequence in the question is NOT an arithmetic sequence. In an arithmetic sequence the difference between each term and its predecessor (the term immediately before) is a constant - including the sign. It is not enough for the difference between two successive terms (in any order) to remain constant. In the above sequence, the difference is -7 for the first two intervals and then changes to +7.
A single number, such as 11111, cannot define an arithmetic sequence. On the other hand, it can be the first element of any kind of sequence. On the other hand, if the question was about ``1, 1, 1, 1, 1'' then that is an arithmetic sequence as there is a common difference of 0 between each term.