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Let the numbers be (x+3) and x:

(x+3)*x = 108

x2+3x-108 = 0

Solving the above quadratic equation works out as:

x = -12 or x = 9

So the numbers are 12 and 9

Check: 12*9 = 108

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13y ago
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Q: What is the unknown positive number when it is increased by 3 and then multiplied by the same unknown number to give a product of 108?
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