98
Always Multiply and divide before adding and subtracting, Unless grouped in parentheses " ( ) ". Always perform calculation within parentheses first.
The problem reads 64-6x3+52. This would be the same as 64-(6x3)+52 (remember to multiply and divide first). Which equals 64-18+52.
64-18=46 which leaves us 46+52=98.
3+52+4 52+3=55+4 55+4=59
67
-52 - 3 + 63 -52 + 66 + 14
52
49 + 3 = 52
To be rational, the numerator has to be a factor of 52 (the last term), and the denominator has to be a factor of 3 (the coefficient of the first term). Try all the combinations, including negative numbers (52/1, -52/1, 52/3, -52/3, 26/1, 26/3, etc.), to see whether one of them is a zero.
If you mean: x-64 = 3 then the value of x is 67
To find the sum of 2 cubed, 3 cubed, and 4 cubed, we calculate each value: (2^3 = 8), (3^3 = 27), and (4^3 = 64). Adding these together gives (8 + 27 + 64 = 99). Therefore, (2^3 + 3^3 + 4^3 = 99).
x + 52 + 2y + 35 = 3 x + 2y = 3 - 52 -35 x + 2y = -84 Infinite number of solutions, are you sure you posted the correct equation?
It is 64.
52
The answer to the mathematical equation 23 plus 29 is 52.